Calculate the energy required for the process
`He_(g)^+ to He_(g)^(2+) + e^(-)`
the ionization energy for the H atom in the ground state is `2.18 xx 10^(-18) J atom^(-1)`

Explanation

Energy of n orbit atom for `(H , He^(+) Li^(2+) ` is `E_(n))`
`E_(n) = (2.18 xx 10^(18) Z^(2))/( n^(2)) J atom^(1)`
for H Z-1 and n=1
IP `2.18 xx 10^(18) J atom^(-1)`
ionization of `He^(+) ` is `He^(+) to He^(2) + e^(-)`
Here ionization for `He^(+)`
`n_(1) 1 ` asnd `n_(2) = prop` z=-2
`Delta E = 2.18 xx 10^(18) (2^(2))/(1^(2)) (1)/( 1^(2))- (1)/(prop^(2))`
`=2.18 xx 10^(18) (4)`
ionization enertgy of `He^(+)`
`=He^(+) to He^(2+) e^(-)` reaction energy