Dual behaviour of matter proposed by de Broglie led to the discovery of electron microscope often used for the highly magnified images of biological moleculas and other type of material .If the velocity of the electron in this microsocope is `1.6 xx 10^(6) ms^(-1)`
Calculate de - Broglie wavelength associated with this electron `(m_(e) = 9.1 xx 10^(31) kg h= 6.626 xx 10^(34) Js )`

Explanation

According to de- Broglie
`lambda = (h)/(mv )`
`n= 6.626 xx 10^(34) J s`
`=6.626 xx 10^(34) kg m^(2) s^(1)`
`=6.626 xx 10^(34) kg m^(2 s^(-1))/(9.1 xx 10^(310 kg ) (2.12 xx 10^(6) ms^(-1))`
`=0.3325 xx 10^(34) xx 31 =6 m`
`=0.3325 xx 10 ^(9) m`
`=0.3325 nm = 332.5 pm`