If the position of the electron is measured within an accuracy of + 0.002 nm calculate the uncertainty in the momentum of the electron Suppose the momentum of the electron is `h// 4pi _(m) xx 0.05 nm` is there any problem in defining this value ?

Explanation

Uncertainty in velocity `(Delta p ) `
According to Heisenberg
`Delta p = (h)/(4pi Delta x)`
`=(6.626 xx 10^(34) js )/( (4xx 3.1428)(0.002 xx 10^(9) m))`
`Delta p = 2.63854 xx 10^(23) kg ms^(-1)`
Real momentum of electron = `(h)/(4pi xx 0.05 nm)`
In this way real momentum `1.054 xx 10^(24) ` is less than calculated value of uncertainty `2.64 xx 10^(23)` So the momentum of electron can not be define properly.