Home
Class 11
CHEMISTRY
in chlorine .^(35)CI and .^(37) CI is ...

in chlorine `.^(35)CI` and `.^(37) CI` is in 3:1 ratio calculate charge atomic mass.

Text Solution

Verified by Experts

three `.^(35) CI` and one `.^(37)CI` total four CI
mass of four CI= 3 (35) + 1 (37) 142 amu
atomic mass of CI` =(142)/( 4) = 35.5 `amu
Promotional Banner

Topper's Solved these Questions

  • STRUCTURE OF ATOM

    KUMAR PRAKASHAN|Exercise Section -C (Multiple Choice Question (MCQs))|24 Videos

  • STRUCTURE OF ATOM

    KUMAR PRAKASHAN|Exercise Section -C(MCQs asked in Competitive Exam)|69 Videos

  • STRUCTURE OF ATOM

    KUMAR PRAKASHAN|Exercise Section -A (Try Your Self -6)|18 Videos

  • STATES OF MATTER

    KUMAR PRAKASHAN|Exercise QUESTION PAPER FROM MODULE (SECTION - A)|4 Videos

  • THE P-BLOCK ELEMENTS

    KUMAR PRAKASHAN|Exercise SECTION-D NCERT EXEMPLAR SOLUTION (MCQs) LONG ANSWER|25 Videos

Similar Questions

Explore conceptually related problems

What is not same in ._(17)^(35) CI and ._(17)^(37) CI ?

What is the mass in grams of a chlorine atom, Cl?

In C^(12) atom if mass of e^(-) is doubled and mass of proton is halved, then calculate the percentage change in mass no. of C^(12)

The velocity associated with a proton moving in a potential difference of 100 v is 4.37 xx 10^(5) ms^(-1) .if the hockey ball of mass 0.1 kg is moving with this velocity , calculate the wavelength associated with this velocity