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It n =6 l =1 p orbital m= 0 .Then ...

It n =6 l =1 p orbital m= 0 .Then the max electron in p orbital are ……

A

6

B

2

C

4

D

10

Text Solution

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The correct Answer is:
B
n= 6,l =1 m= + 1 0 = 1
`P_(x ) p_(y) p_(z ) `
Total `e^(-) ` in p orbital are 6 I `p_(y)` =2 electron
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