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Magnitude of K.E. in an orbit is equa...

Magnitude of K.E. in an orbit is equal to

A

Half of the potential energy

B

Twice of the potential energy

C

One fourth the potential energy

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A

K.E. of `e^(-) =(1)/(2)` of P.E. K.E is always positive or K.E. `-((1)/(2) P.E)` = - Total energy of system
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KUMAR PRAKASHAN-STRUCTURE OF ATOM-Section -C(MCQs asked in Competitive Exam)
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  13. An electron from one Bohr stationary orbit can go to next higher ...

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