For an electron v= 300 `ms^(-1)` and certainty in velocity is 0.001 % what is the uncertainty in position

Options

A. `5.76xx 10^(2) m`
B. `1.92 xx 10^(2) m`
C. `3.84 xx 1^(2) m`
D. `19.2 xx 10^(-2) m`

Answer

B

Explanation

`Delta X xx m Delta v = (h)/(4pi)`
`Delta x = (h)/(4pi m Delta v )`
`Delta v = 0.001 % of 300 `
`=(300 xx 0.001)/( 100)`
`m=9.1 xx 10^(31) kg`
`=(6.626 xx 10^(34))/(4xx 3.14 xx 9.1xx 10^(31) xx 300 xx 0.001 xx 10^(2))`
`=1.932 xx 10^(2) m`