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The ionization energy hydrogen atom ...

The ionization energy hydrogen atom is 13.6 ev .The ionization energy of He

A

13.6 eV

B

54.4eV

C

122.4eV

D

zero

Text Solution

Verified by Experts

The correct Answer is:
B
`E_(He = (+13.6z^(2) He^(+))/(n^(2) He^(+))`
`E_(H) = (13.6 Z^(2)H)/( n^(2)H)`
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