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The energies E(1) and E(2) respectively....

The energies `E_(1)` and `E_(2)` respectively. The relation between their wavelengths, i.e. `lambda_(1)` and `lambda_(2)` will be

A

`lambda_(1)=1/2lambda_(2)`

B

`lambda_(1)=lambda_(2)`

C

`lambda_(1)=2lambda_(2)`

D

`lambda_(1)=4lambda_(2)`

Text Solution

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The correct Answer is:
C
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