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The decrease in number of neutrons when ...

The decrease in number of neutrons when `._(a)^(x)U` changes the `._(b)^(y)Pb` is represented as :

A

(x-a)+(y+b)

B

(x-a)-(y+b)

C

(x+a)-(y-b)

D

(x-a)-(y-b)

Text Solution

Verified by Experts

The correct Answer is:
D
No. of neutrons in = `._(a)A^(X)U=(x - a)`
No. of neutrons in `._(b)^(y)Pb = (y - b)`
`therefore` The change in no. of neutrons = (x - a) - (y - b)
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