What is frequency of first line of Balmer series for H-atom ?

Options

A. `3.29 xx10^(15) s^(-1)`
B. `8.05 xx10^(13) s^(-1)`
C. `8.22 xx10^(15) s^(-1)`
D. `4.57 xx10^(14) s^(-1)`

Answer

D

Explanation

First line of balmer series of h atom
`therefore` form n=3 to n=2 electron transition
`v=(triangleE)/(h)`
`=(2.18 xx10^(-18)j)/(6.626xx10^(-34)js)(1)/(3^(2))-(1)/(2^(2))`
`=-0.4569 xx10^(15)`
`=-4.57 xx10^(14)s^(-1)`