Wavelengths of different rad iatio n s are given below : `lambda(A) - 300 nm lambda(B) = 300 mum lambda(C) = 3 nm lambda(D) = 30A` Arrange the seradiations in th eincreasing order of their energies.

Explanation

`lambda(A) = 300 nm = 300 xx 10^(-9)` m
`lambda(B) = 300 mu m = 300 xx 10^(-6)m`
`lambda (C) = 3nm = 3 xx 10^(-9) m`
`lambda(D) = 30A = 30 xx I10^(-10) m = 3 xx 10^(-9) m` he 1 Energy, `E = (hc)/(lambda)` So, `E prop (1)/(lambda)`
-Increasing order of energy is `B lt A lt C = D`