If distance between two molecules of gases becomes half then which type of changes occurs in London forces ?

Explanation

London forces `prop (1)/(r^(6))= k (1)/(r^(6))`
Initially London force `= x_(1)=k(1)/(r^(6))`
Initial distasnce = r
Final distance `= (r )/(2)`
Final london force `x_(2)=k(1)/(((r )/(2))^(6))=k(2^(6))/(r^(6))`
`(x_(2))/(x_(1))=((k.2^(6))/(r^(6)))xx((r^(6))/(k))`
`= 2^(6)=2xx2xx2xx2xx2xx2 = 64` times