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Explain kinetic energy and average trans...

Explain kinetic energy and average translation kinetic and average square speed.

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Kinetic energy : Kinetic energy of molecule is represent as follow.
Kinetic energy `=(1)/(2)mu^(2) " "` ……(Eq. -i)
Average translation kinetic energy : `(1)/(2)m u^(2)` is known as translation kinetic energy.
where, `bar(u)^(2)=` Average speed of root of all molecules in molecules in motion in straight line.
Average square speed `(bar(u)^(2))` : Average square speed is measurement of average kinetic speed of gaseous molecules.
If velocity of n molecules are `u_(1), u_(2), u_(3)`, .... than its quare `u_(1)^(2), u_(2)^(2), u_(3)^(2), ...... u_(n)^(2)` so,
`bar(u)^(2)=(u_(1)^(2)+u_(2)^(2)+u_(3)^(2).....u_(n)^(2))/(n)`
`bar(u)^(2)=(u_(rms))^(2)=(3RT)/(M)`
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