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At 21^(@)C temperature volume of 212 g O...

At `21^(@)C` temperature volume of `212 g O_(2)` gas is `34 dm^(3)` . If pressure of gas becomes 1.24 bar then how many gram `O_(2)` gas is left from container ? `(R=0.083 dm^(3)" bar " K^(-1)mol^(-1))`
[Note : Calculate intital moles by pV = nRT]

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The correct Answer is:
156.74 g
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