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Calculate the temperature of 4.0 mol of ...

Calculate the temperature of 4.0 mol of a gas occupying `5 dm^(3)` at 3.32 bar. (R = 0.083 bar `dm^(3)K^(-1)mol^(-1)`).

Text Solution

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According to combined gas equation, pV = nRT
`therefore T=(pV)/(nR)`
Where Pressure of gas (p) = 3.32 bar
Volume of gas `(V) = 5 dm^(3)`
Moles of gas (n) = 4.0 mol
gas constant (R ) = 0.083 bar `dm^(3)K^(-1)mol^(-1)`
`therefore T=(("3.32 bar")(5 dm^(3)))/((4.0 mol)(0.083" bar dm"^(3)K^(-1)mol^(-1)))`
`= 50 K = (50-273)=-223^(@)C`.
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