Calculate the total number of electrons present in 1.4 dinitrogen gas. (N of Z = 7).

Explanation

Moleculasr formula of Dinitrogen gas `= N_(2)`
Molecular mass is 28 g `mol^(-1)`
Moles of `N_(2)=("Weight")/("Molecular mass of "N_(2))`
`= (1.4 g)/(28 g mol^(-1))=0.05` mole `N_(2)` gas
Atomic number of Nitrogen (Z) = 7
1 mole of Dinitrogen `7xx2=14` electron
`therefore` 1 mole `= 6.023xx10^(23)` molecules of `N_(2)`
Number of electrons in 1 mole Dinitrogen
`= 14xx6.022xx10^(23)`
But number of electrons present in 0.05 moles Dinitrogen
`bar(e )=14xx("0.05 mole")xx(6.022xx10^(23)bar(e )mol^(-1))`
`= 14xx0.3011xx10^(23)` electrons
`=4.2154xx10^(23)` electrons.