Density of a gas is found to be 5.46 `g//dm^(3)` at `27^(@)C` at 2 bar pressure. What will be its density at STP ?

Explanation

where, `T_(1)=27^(@)C=(273+27)=300 K`
`p_(1)=2 " bar, " d_(1)=5.46 g//dm^(3)`
STP is `T_(2)=273 K`
Pressure `p_(2)=1.0` bar (New in method)
Density `d_(2)=(?)`
(In old method, STP means 1 atm = 1.01325) relation between density and pressure according to 5.32 equation. pM = dRT
`therefore (p)/(td)=(R )/(M)=K` constant (`because` if there is only one gas value of R and M is not changed)
`therefore (p_(1))/(T_(1)d_(1))=(p_(2))/(T_(2)d_(2))`
`therefore ("2 bar")/((300 K)(5.46 g//dm^(3)))=("1.0 bar")/((273 K)(d_(2)))`
`therefore d_(2)=("1.0 bar")/("2 bar")xx(300 K)/(273 K)xx5.46 g//dm^(3)`
`= 2.029999 g//dm^(3)~~ 3.0 g//dm^(3)`