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Pay load is defined as the difference be...

Pay load is defined as the difference between the mass of displaced air and the mass of the balloon. Calculate the pay load when a balloon of radius 10 m, mass 100 kg is filled with helium at 1.66 bar at `27^(@)C`. (Density of air = 1.2 kg `m^(-3)` and R = 0.083 bar `dm^(3)K^(-1)mol^(-1)`).

Text Solution

Verified by Experts

Calculation of balloon.s volume :
Radius of balloon r = 10 m
Volume of balloon `= (4)/(3)pi r^(3)=(4)/(3)((22)/(7))(10 m)^(3)`
`= 4190.48 m^(3)`
Calculation of weight of displaced air :
`therefore` Volume of He gas in balloon = Volume of balloon
`= 4190.48 m^(3)`
`~~4190.5 m^(3) = V`
`therefore (("The weight of air"),("displaced by balloon"))=(("Volume of"),("balloon (V)"))xx(("Air of "),("density"))`
`=(4190.5 m^(3))(1.2 kg m^(-3))`
`= 5028.6` kg air
Calculation of weight (w) of He gas in balloon :
where, Volume of Balloon (V) `= 4190.5 m^(3)=4190.5xx10^(3)`
Pressure of `H_(2)` gas in `dm^(3)` in balloon (p) = 1.66 bar
Temperature (T) of He in Balloon,
`(T)=(27+273)=300K`
Moles of He in Balloon `= ("Weight (w)")/("Molecular Mass (M)")`
Gas Constant (R ) = 0.083 bar `dm^(3)K^(-1)mol^(-1)`
Molecular mass (M) of He gas = 4.0 gm `mol^(-1)`
`= 4.0xx10^(-3)kg mol^(-1)`
`pV = nRT=(wRT)/(M)`
`therefore w=(pVM)/(RT)`
`therefore w=(("1.66 bar")(4190.5xx10^(3)dm^(3))(4.0xx10^(-3)kg mol^(-1)))/(("0.083 bar dm"^(3)K^(-1)mol^(-1))(300K))`
`= 1117.47 kg ~~ 1117.5 kg`
Total calculation of balloon and He :
Total weight = (weight of balloon) + (weight of He)
`= 100 kg + 1117.5 kg`
`= 1217.5 kg`
Calculation of pay load :
Pay load `= (("Mass of air"),("displaced"))-(("Total weight of"),("He nad balloon"))`
`= 5028.6 kg - 1217.5 kg`
= 3811.1 kg
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