300 K temperature at `2.0xx10^(4)` Pa pressure volume of 0.09 mole `CO_(2)` gas is `112.0xx10^(-3)m^(3)` then calculate volume at `4.0xx10^(4)` Pa ?

Explanation

`64.2xx10^(-3)m^(3)`
`p_(1)V_(1)=p_(2)V_(2)`
`therefore V_(2)=(p_(1)V_(1))/(p_(2))=(2.0xx10^(4)Pa xx112.0xx10^(-3)m^(3))/(4.0xx10^(4)Pa)`
`= 64.2xx10^(-3)m^(3)`
(Note : As the pressure divided the volume become half.)