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The pressure exerted by 6.0 g of methane...

The pressure exerted by 6.0 g of methane gas in a `0.03 m^(3)` vessel at `129^(@)C` is (Atomic masses : C = 12.01, H = 1.01 and R = 8.314 `JK^(-1)mol^(-1)`)

A

31684 Pa

B

215216 Pa

C

13409 Pa

D

41648 Pa

Text Solution

Verified by Experts

The correct Answer is:
D
`P=(nRT)/(V)`
`= (6)/(16.02)=(8.314xx402)/(0.03)=41648` Pa
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