3 g of activated chasrcoal was added to 50 mL of acetic acid solution (0.06N) in a flask. After an hour it was filtered and the strength of the filtrate was found to be 0.042 N. The amount of acetic acid adsorbed (per gram of charcoal) is :

Options

A. 18 mg
B. 36 mg
C. 42 mg
D. 54 mg

Answer

A

Explanation

Number of moles of acetic acid adsorbed `= (0.06xx(50)/(1000)-0.042xx(50)/(1000))`
`= (0.9)/(1000)` moles.
`therefore` Weight of acetic acid adsorbed `= 0.9xx60 mg`
= 54 mg
Hence, the amount of acetic acid adsorbed per g of charcoal `= (54)/(3)` mg = 18 mg
Hence, option (A) is correct.