The pressure of a 1 : 4 mixture of dihydrogen and dioxygen enclosed in a vessel is one atmoshpere. What would be the partial pressure of dioxygen ?

Options

A. `0.8xx10^(5)` atm
B. `0.008 Nm^(-2)`
C. `8xx10^(4)Nm^(-2)`
D. 0.25 atm

Answer

C

Explanation

Moles ratio of `H_(2)` and `O_(2)` is 1 : 4. Hence partial pressure of dioxygen is
`therefore` Partial pressure of `O_(2)=` Mole fraction of `O_(2)xx` total pressure of mixture
`= (4)/(1+4)xx1=(4)/(5)xx1` atm
`= 0.8 atm = 0.8xx105 Nm^(-2)=8xx10^(4)Nm^(-2)`