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The reaction of cyanamlde, NH(2) CN((s))...

The reaction of cyanamlde, `NH_(2) CN_((s))`, with dioxygen was carried out in a bomb calorimeter, and `DeltaU` was found to be `-742.7 "kJ mol"^(-1)` at 298 K. Calculate enthalpy change for the reaction at 298 K.
`NH_(2) CN_((g)) + (3)/(2) O_(2(g)) to N_(2(g)) + CO_(2(g)) + H_(2) O_((l))`

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Verified by Experts

`Deltan_((g)) = n_(p) - n_(r)`
`=2-(3)/(2) = +(1)/(2) "mol"`
`Deltan_((g)) = Delta U + Deltan_((g)) "RT"`
`= -742.7 + (+(1)/(2) ) (8.314 xx 10^(-3) ) (298)`
`= -742.7 + 1.2`
`= -741.5 "kJ mol"`
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