Calculate the work, when 1 mole ideal gas defuse to 1 atm from 10 atm at 300. K temperature.

Options

A. 5744.1 J
B. 6257.2 J
C. 4938.8 J
D. 4138.8 J

Answer

A

Explanation

When isothermal expansion of ideal gas is done, For isothermal process,
`w_("rev") = - 2.303 "nRT" log""(P_1)/(P_2)`
where, `n =1` mole ideal gas
`R=8.314` Joule kelvin`""^(-1) "mol"^(-1)`
`T= 300K`
`P_1=`Initial pressure = 10 atm
`P_2=` Final pressure = 1 atm
`therefore w_("rev") = - 2.303 (1 "mole") (8.314 "Joule Kelvin"^(-1) "mole"^(-1) ) (300 K) log ""(10)/(1)`
`= - 2.303 xx 8.314 xx 300 xx 1` J
`= -5744.1` J
Value of w is -ve. So, work done by system = 5744.1 J