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The following reaction is performed at 2...

The following reaction is performed at 298 K.
`2NO_((g)) + O_(2(g)) hArr 2NO_(2(g))`
The standard free energy of formation of `NO_((g))` is 86.6 kJ/mol at 298 K. What is the standard free energy of formation of `NO_(2(g))` at 298 K ?
`(K_(p) = 1.6 xx 10^(12) )`

A

`R (298) "In" (1.6 xx 10^(12) ) - 86600`

B

`86600 + R (298) "In" (1.6 xx 10^(12) )`

C

`86600 - ("In" (1.6 xx 10^(12) ))/( R(298))`

D

`0.5 [2xx 86600- R (298) "In" (1.6 xx 10^(12) )`

Text Solution

Verified by Experts

The correct Answer is:
D

`2NO_((g)) + O_(2(g)) hArr 2NO_(2(g))`
`(Delta G^(@) )_("reaction") = [(Delta G^(@) )_("formation") ]_("product")-[(DeltaG^(@))_("formation")]_("reactant")`
`rArr - RT "In" K_(p) = 2 xx (Delta G^(@) )NO_(2) - 2(Delta G^(@) ) NO`
`rArr (Delta G^(@) ) NO_(2) = 2(Delta G^(@) )_(NO)`
`= -RT " In " K_(p)`
`rArr (Delta G^(@) )_(NO_2) = (2 xx 86600- R (298)"In" K_(p) )/(2) `
`= (2xx 86600 - R (298) "In" 1.6 xx 10^(12) )/( 2)`
`=0.5 [2 xx 86,600 - R (298) "In" (1.6 xx 10^(12) )]`
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