The enthalpy of atomisation for the reaction `CH_(4(g)) to C_((g)) + 4H_((g))` is `1665 "kJ mol"^(-1)`. What is the bond energy of `C-H` bond?

Explanation

In `CH_(4)`, there are four `C-H` bonds.
The enthalpy of atomisation of 1 mole of `CH_(4)` means dissociation of four moles of `C-H` bond.
`therefore C-H` bond energy per mol `= (1665 "kJ")/( 4 "mol")`
`=416.25 "kJ mol"^(-1)`