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Given that Delta H = 0 for mixing of two...

Given that `Delta H = 0` for mixing of two gases. Explain whether the diffusion of these gases into each other in a closed container is a spontaneous process or not ?

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The mixing of two gases have `Delta H = 0`. Therefore, it is spontaneous process because energy factor has no role to play but randomness increases i.e., randomness factor favours the process.
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KUMAR PRAKASHAN-THERMODYNAMICS-Section - D Solutions of NCERT Exemplar Problems ( Short Answer Type Questions )
  1. The enthalpy of atomisation for the reaction CH(4(g)) to C((g)) + 4H((...

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  2. Use the following data to calculate Delta("lattice") H^( Theta ) for N...

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  3. Given that Delta H = 0 for mixing of two gases. Explain whether the di...

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  7. A sample of 1.0 mol of a monoatomic ideal gas is taken through a cycli...

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  8. The standard molar entropy of H(2) O((l)) is 70 "JK"^(-1) "mol"^(-1). ...

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  9. Which of the following is not a state functions?

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  11. Which quantity out of Delta(r) G and Delta(r) G^( Theta ) will be zero...

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  12. Predict the change in internal energy for an isolated system at consta...

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  13. Although heat is a path function but heat absorbed by the system under...

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  14. Expansion of a gas in vacuum is called free expansion. Calculate the w...

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  15. Heat capacity (Cp) is an extensive property but specific heat (c) is a...

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  16. The difference between Cp and Cv can be can be H=U + pV. Calculate the...

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  17. If the combustion of 1 g of graphite produces -20. 7 kJ of heat, what ...

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  18. The net enthalpy change of a reaction is the amount of energy required...

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  20. The enthalpy of reaction for the reaction : 2H((g)) + O(2(g)) to 2H(2)...

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