How many electrons are required for the reduction of 1 mole of `MnO_(4)^(-)" to "Mn^(2+)` ?

Options

A. `3.011xx10^(24)`
B. `6.022xx10^(24)`
C. `1.2044xx10^(24)`
D. `1.8066xx10^(24)`

Answer

A

Explanation

`therefore` Reduction half reaction :
`MnO_(4)^(-)+5bare+8H^(+)toMn^(2+)+4H_(2)O`
Thus reduction of 1 mole of `MnO_(4)^(-)`
requires 5 mole of electrons
But 1 mole electron = `6.022xx10^(23)` electron
`therefore5" mole electron"=(5xx6.022xx10^(23))/1`
= `30.10xx10^(23)`
= `3.011xx10^(24)` electrons