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Balance the following ionic equation. ...

Balance the following ionic equation.
(a) `Cr_(2)O_(7)^(-2)+H^(+)+I^(-)toCr^(+3)+I_(2)+H_(2)O`
(b) `Cr_(2)O_(7)^(-2)+Fe^(+2)+H^(+)toCr^(+3)+Fe^(+3)+H_(2)O`
( c) `MnO_(4)^(-)+SO_(3)^(-2)+H^(+)toMn^(+2)+SO_(4)^(-2)+H_(2)O`
(d) `MnO_(4)^(-)+H^(+)+Br^(-)toMn^(+2)+Br_(2)+H_(2)O`

Text Solution

Verified by Experts

(a)
R.H.E. : `Cr_(2)O_(7)^(-2)toCr^(+3)`
O.H.E. : `I^(-)toI_(2)`
R.H.E. : `Cr_(2)O_(7)^(-2)+14H^(+)+6e^(-)to2Cr^(+3)+7H_(2)O`
O.H.E. : `2I^(-)toI_(2)+2e^(-)`

O.H.E. : `Fe^(+2)toFe^(+3)`
R.H.E. : `Cr_(2)O_(7)^(-2)toCr^(+3)`
O.H.E. : `Fe^(+2)toFe^(+3)+e^(-)`
R.H.E. : `Cr_(2)O_(7)^(-2)+6e^(-)to2Cr^(+3)`
Balance charges :
`Cr_(2)O_(7)^(-2)+14H^(+)+6e^(-)to2Cr^(+3)`
Balance H and O : `Cr_(2)O_(7)^(-2)+14H^(+)+6e^(-)to2Cr^(+3)+7H_(2)O`
Total reaction :

R.H.E. : `MnO_(4)^(-)toMn^(+2)`
O.H.E. : `SO_(3)^(2-)toSO_(4)^(-2)`
R.H.E. : `MnO_(4)^(-)+8H^(+)+5e^(-)toMn^(+2)+4H_(2)O`
O.H.E. : `SO_(3)^(-2)toSO_(4)^(-2)+2e^(-)`
Balance charges of reaction.
`SO_(3)^(-2)toSO_(4)^(-2)+2H^(+)+2e^(-)`
Balance H and O by `H_(2)O`.
`SO_(3)^(-2)+H_(2)OtoSO_(4)^(-2)+2H^(+)+2e^(-)`
Total reaction :

R.H.E. : `MnO_(4)^(-)toMn^(+2)`
O.H.E. : `Br^(-)toBr_(2)`
R.H.E. : `MnO_(4)^(-)+8H^(+)+5e^(-)toMn^(+2)+4H_(2)O`
O.H.E. : `2Br^(-)to2Br_(2)+2e^(-)`
Total reaction :
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