The concentration of `OH^-` in water at 298 K

Options

A. `10^(-14)`
B. 55.55
C. `10^(-7)`
D. All of these

Answer

C

Explanation

Because of self ionization of `H_2O, [H_3O^+] = [OH^-]= 1.0xx10^(-7) "mol L"^(-1)` , is obtained at equilibrium condition.
`H_2O_((l)) + H_2O_((l)) = H_3O_((aq))^(+) + OH_((aq))^(-)`