Hydrogen peroxide oxidises `[Fe(CN)_6]^(4-)` to `[Fe(CN)_6]^(3-)` in acidic medium but reduces `[Fe(CN)_6]^(3-)` to `[Fe(CN)_6]^(4-)` in alkaline medium. The other products formed are, respectively.

Options

A. `(H_2O+O_2)` and `H_2O`
B. `(H_2O + O_2)` and `(H_2O+ OH^-)`
C. `H_2O` and `(H_2O+ O_2)`
D. `H_2O` and `(H_2O+OH^-)`

Answer

C

Explanation

`[Fe(CN)_6]^(4-) + 1/2H_2O_2 + H^(+) to [Fe(CN)_6]^(3-) + H_2O`
`[Fe(CN_6)]^(3-) + 1/2 H_2O_2 + OH^(-) to [Fe(CN)_6]^(4-) + H_2O + 1/2O_2`