How can you determine the rate law of the following reaction?
`2NO_((g))+O_(2(g))to2NO_(2(g))`

Explanation

The rate law can be determined by .measring the rate of this reaction as a function of initial concentration by keeping the concentration of one of the reactants constant and changing the concentration dependance of rate,rate law can be determined.
Example:If the concentraton of NO is doubled ,keeping the concentration of oxygen continously ,the process velocity four time.
Which accelerate ,so the rate =k`[NO]^(2)[O_(2)]` and the introduction of the acceleration rule is as follows.
`-(1)/(2)(Delta[NO])/(dt)=-(Delta[O_(2)])/(Deltat)=(1)/(2)=(Delta[NO_(2)])/(Deltat)`