The values of the rate constant of the reaction `C_(2)H_(5)I+OH^(-)toC_(2)H_(5)OH+I^(-)` at `30^(@)` and `60^(@)C` temperatures are 0.325 and 6.735 litre `"mole"^(-1)` `"second"^(-1)` than what will be the value of activation energy?

Options

A. 20260 cal
B. 20260 K cal
C. 361.44 cal
D. 84773 cal

Answer

A

Explanation

`(logK_(2))/(K_(1))=(E_(a))/(2.303R)((1)/(T_(1))-(1)/(T_(2)))`
`therefore (log 6.735)/(0.325)=(E_(a))/(2.303)xx1.987((1)/(303)-(1)/(333))`
`therefore E_(a)`=20260 cal