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Expain the formation of the two products...

Expain the formation of the two products in the following reaction :
`CH_3 CH=CHCH_2 Cl +H_2 O to CH_3 -CH =CHCH_2 OH +CH_3 CH (OH) CH=CH_2`

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Hydrolysis of 1-chloro-2-butene takes place through `S_(N^(1))` mechanism involving the formation of allylic carbocation as intermediate which is stabilised by resonance.
`CH_(3)-CH= CH-CH_(2)Cl overset(OH^(-))rarr [CH_(3)-CH=CH-overset(+)(C )H_(2) harr CH_(3) - overset(+)(C )H- CH= CH_(2)]`
The positive charge is equally distributed over C-1 and C-3. THe nucleophile can attack on C-1 or C-3 resulting in the formation of two products.
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