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Which product will form when optically a...

Which product will form when optically active form of `C_4 H_9 Br` is subjected to dehydrohalogenation?

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The optically active form of `C_(4)H_(9)Br " is " CH_(3)CH_(2)CHBrC_(3)`. 2-Bromobutane on dehydrohalogenation gives 2-butene according to Saytzeff rule.
`CH_(3)CH_(2)CHBrCH_(3) underset(KOH)overset("alcoholic")rarr CH_(3)CH=CHCH_(3) + KBr + H_(2)O`
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AAKASH SERIES-ALKYL AND ARYL HALIDES-Problem
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