Solubility of iodine of water is `1.1 times 10^-3 mol L^-1` at 290K. When 0.1g of iodine is stirred in 200ml water till the equilibrium is reached at 290K, calculate the mass of undissolved iodine.

Explanation

Solubility of iodine= `1.1 times 10^-3 mol L^-1`
`=1.1 times 10^-3 times 254=0.279 g L^-1`
The amount of iodine dissolved in 200ml water= `(0.0279 times 200)/1000=0.0558 g`
Amount of iodine added =0.1 g
Amount of iodine undissolved in the formation of solution= 0.1-0.0558=0.0442g.