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4.25 grams of ammonia are dissolved to f...

4.25 grams of ammonia are dissolved to form 4L aqueous solution. Calculate the active mass.

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Molecular weight of ammonia =`17g mol^-1`
n= Number of moles = `(Weight of ammonia)/(Gram mol ecular weight)=4.25/17=0.25`
V=Volume =4L
Active mass = `n/V=0.25/4=0.0625 mol L^-1`
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