The reaction was started with 0.1M each of CO and `H_2O` at 800K. `K_c` for the chemical reaction , `CO(g)+H_2O(g) leftrightarrow CO_2(g)+H_2(g)` at 800K is 4.24.Calculate the equilibrium concentration of the lightest gas.

Explanation

`CO_2(g)+H_2O(g) leftrightarrow CO_2(g)+H_2(g)`
0.1 0.1 0 0 at start
`0.1-x 0.1-x x x` at equilibrium
The equilibrium constant `K_c` is given as
`K_c=([CO_2][H_2])/([CO][H_2O])= x^2/(0.1-x)^2=4.24, x/(0.1-x) =sqrt4.26=2.06` Concentration of `H_2=x=0.067M`