A sample of hard water contains `1 xx 10^(-3)` mole of `CaCl_2` per 10kg of water. Calculate the degree of hardness of water sample

Explanation

Weight of `CaCl_(2)` present in 10kg of water =`10^(3)` moles = 111`xx10^(-3)g`
Weight of `CaCl_(2)` present in `10^(6)` of water `=(111xx10^(-3)xx10^(6))/(10(4))=11.1g`
111g of `CaCl_(2)-=100g ` of `CaCO_(3),11.1g` of `CaCl-=10g` of `CaCO_(3)`
The degree of hardness of given sample=10ppm