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0.2g of an organic compound on analysis ...

0.2g of an organic compound on analysis give 0.147g of carbondioxide, 0.12 g of water and 74.6 c,c of nitrogen at S.T.P. Calculate the weight percentages of constituents.

Text Solution

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Weight of compound = W = 0.2g
Weight of `CO_(2) = W_(1) = 0.147` g
Weight of `H_(2)O = W_(2) = 0.12g`
Volume of `N_(2)` at STP = 76.6 c.c.
% of Carabon = `(W_(1)xx 12xx100)/(Wxx44)=(0.147xx12xx100)/(0.2xx44)=20.04%`
% of Hydrogen = `(W_(2)xx2xx100)/(Wxx18)=(0.12xx2xx100)/(0.2xx18)=6.66%`
% of Nitrogen = `(V_(2)xx28xx100)/(Wxx22400)=(74.6)/(8xx0.2)=46.63%`
% of Oxygen = 100 - (%C + % H + % N) = 100 - 73.33 = 26.67%
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