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0.25g of an organic compound gave 30cm^(...

0.25g of an organic compound gave `30cm^(3)` of moist dinitrogen at 288K and 745mm pressure. Calculate the percentage of nitrogen. (Aqueous tension at 288K = 12.7mm)

Text Solution

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Mass of the substance = 0.25g , Volume of moist dinitrogen = `30cm^(3)`
Temperature = 288K , Pressure = 745 - 12.7 = 732.3mm
Volume of dinitrogen at `S.T.P(V_(2)),V_(2)=(P_(1)V_(1))/(T_(1))xx(T_(2))/(P_(2))=(732.3xx30xx273)/(288xx760)=27.4m^(3)`
`27.4cm^(3)` of dinitrogen at STP weighs = `(28xx27.4)/(22400)=0.034g`
Percentage of nitrogen in organic compound = `(0.034)/(0.25) xx 100 = 13.6`
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