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As per law of mass action, for NH(4) HS(...

As per law of mass action, for `NH_(4) `HS(s) `hArr NH_(3)(g) + H_(2) S(g)` ratio of rate constants of forward `(K_(f))` & backword `(K_(b))` reactions at equilibrium equals ot

A

`[NH_4HS]`

B

`P_(NH_3)+P_(H_2S)`

C

`[H_2S]+[NH_3]`

D

`[NH_3] [H_2S]`

Text Solution

Verified by Experts

The correct Answer is:
D
`(K_(f))/(K_(b))=K_(eq)=[NH_(3)][H_(2)S]`
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