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Sulphide ion in alkaline solution rea...

Sulphide ion in alkaline solution reacts with solid sulphur to form polysulphide ions having formulae `S_2^(2-)`, `S_3^(2-)`, `S_4^(2-)` and so on. The equilibrium constant for the formation of `S_2^(2-)` is `12(K_1)` and for the formation of `S_3^(2-)` is `132(K_2)` both from S and `S^(2-)`. What is the equilibrium constant for the formation of `S_3^(2-)` from `S_2^(2-)` and S ?

A

11

B

12

C

132

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A
`S+S^(2-) harr S_(2)^(2-), K_(1)=12`
`2S+S^(2-) harr S_(3)^(2-), K_(2)=132`
`S_(2)^(2-)+S harr S_(3)^(2-), K=(K_(2))/(K_(1))=(132)/(12)=11`
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