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The equilibrium conatant for the reactio...

The equilibrium conatant for the reaction `H_(2(g)) + I_(2(g)) hArr 2HI_((g))` is 2 at a certain temperature. The equilibrium concentrations of `H_(2)` and HI are 2 mole .`lit^(-1)`. What is the equilibrium concentration (in mole `lit^(-1)`) of `I_(2)` ?

A

16

B

4

C

8

D

1

Text Solution

Verified by Experts

The correct Answer is:
D
`K_(c)=([HI]^(2))/([H_(2)][I_(2)]), 2 = ((2)^(2))/((2) xx [I_(2)]), [I_(2)]=1`
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