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1 mole CaCO(3(s)) is heated in 11.2 ...

1 mole `CaCO_(3(s))` is heated in 11.2 lit vessel so that equilibrium is established at 819 K. If `K_p` for `CaCO_3 harr CaO + CO_2` at this temperature is 2 atm, equilibrium concentration of `CO_2` (in mol-`lit^(-1)`)

A

`1//3`

B

`1/(11.2)`

C

`1/(33.6)`

D

`1/(22.4)`

Text Solution

Verified by Experts

The correct Answer is:
C
`CaCO_(3(s)) harr CaO_((s))+CO_(2(g))`
`K_(P)=PCO_(2)=2`
we know that `K_(P)=K_(c)(RT)^(Deltan)`
`K_(c)=(K_(P))/((RT)^(Delta n))=(2)/((0.0821 xx 819)^(1))=(1)/(33.6)`
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