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20 gm of CaCO(3) is allowed to dissocia...

20 gm of `CaCO_(3)` is allowed to dissociate in a 5.6 litres container at `819^(@)` C. If 50% of `CaCO_(3)` is dissocitated at equilibrium the `'K_(p)'` value is

A

5 atm

B

1.6 atm

C

4.8 atm

D

10 atm

Text Solution

Verified by Experts

The correct Answer is:
B

Molar con. at equlibrium - `(x)/(5.6)`
Given x=50% of 0.2 =0.1, `K_(c)=(CO_(2)]=(x)/(5.6)=(0.1)/(5.6)`
but `K_(P)=K_(c)(RT)^(Delta n)=(0.1)/(5.6) xx (0.0821 xx 1092)^(1)=1.6` atm
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