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The equilibrium constant K (in atm) for ...

The equilibrium constant K (in atm) for the reactio is 9 at 7 atm and 300 K, `A_(2(g)) hArr B_(2(g)) + C_(2(g))`. calcuate the average molar mass (in gnm/mol) of an equilibrium mixture.
Given: Molar mass of `A_(2) B_(2) and C_(2)` are 70, 49 and 21 gm/mol fespectively.

A

50

B

45

C

40

D

37.5

Text Solution

Verified by Experts

The correct Answer is:
A

Total moles = `1-alpha`
`K_(P)=(P_(B_(2)).P_(C_(2)))/(P_(P_(2))) implies 9=(((alpha)/(1+alpha).7)((alpha)/(1+alpha)7))/(((1-alpha)/(1+alpha)) xx 7)`
`= alpha=3//4 implies alpha=(3)/(4) implies alpha=(D-d)/(d(n-1)) implies d = 40`
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