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AB(2(g)) dissociates as AB(2(g)) harr AB...

`AB_(2(g))` dissociates as `AB_(2(g)) harr AB_(2(g))+B_((g))`. The initial pressure of `AB_2` is 600 mm Hg and equilibrium pressure of the mixture of gases is 800 mm Hg. Then

A

`alpha = 33.3%`

B

`K_p = 100mm`

C

equilibrium pressure of `AB_2` is 400mm

D

equilibrium pressure of B is 200mm

Text Solution

Verified by Experts

The correct Answer is:
A, B, C, D

`P_(eqn)=600+P=800 implies P=200 prop (200)/(600)=1//3`
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