Home
Class 11
CHEMISTRY
2O3 harr 3O2 Ozone dissociates until the...

`2O_3 harr 3O_2` Ozone dissociates until the molecular weight of the equilibrium mixture becomes 40. Initial pressure of `O_3` is 600 mm Hg. Then

A

`K_p = 360` mm

B

degree of dissociation = 0.4

C

`P_(eq) = 720` mm

D

`K_p = p_(O)_3 = P_(O)_2`

Text Solution

Verified by Experts

The correct Answer is:
A, B, C, D

`(D)/(d)=1+(n-1)alpha, (48)/(40)=1+((3)/(2)-1)alpha, alpha=40%`
`2O_(3) harr 3O_(2)`
at eqm `underset(=360)(600(1-alpha))" "underset(360)((3alpha)/(2) xx 600)`
`K_(P)=((360)^(3))/((360)^(2))=360`
Promotional Banner

Similar Questions

Explore conceptually related problems

N_(2)O_(4) harr 2NO_(2), N_(2)O_(4(g)) dissociates until the partial pressures of N_(2)O_(4) and NO_(2) become equal, initial pressure of N_(2)O_(4) is 9 atmosphere. What is K_(P) ?

In the reaction 2 SO_(3 (g)) , hArr 2 SO_(2 (g)) + O_(2 (g)) , SO_(3 (g)) is 50 % dissociated at 27^(@)C when the equilibrium pressure is 0.5 atm . Partial pressure of SO_(3 (g)) at Equilibrium is

AB_(2(g)) dissociates as AB_(2(g)) harr AB_(2(g))+B_((g)) . The initial pressure of AB_2 is 600 mm Hg and equilibrium pressure of the mixture of gases is 800 mm Hg. Then

At 400K, in a 1.0L vessel N_2O is allowed to attain equilibrium N_(2)O_(4(g))hArr 2NO_(2(g)) . At equilibrium the total pressure is 600 mm Hg, when 20% of N_2O_4 is disscociated. The K_rho value for the reaction is

N_(2)O_(4) hArr 2NO_(2). At 300K N_(2)O_(4) at 6 atmosphere is heated to 600K where equilibrium is established with a total pressure of 16 atmospheres. What is K_(p) at 600K ?

3O_(2) harr 2O_(3) . Oxygen is ozonised until the partial pressures of both gases become equal at equilibrium. Which statements are correct if P_(eq) = 10 atm ?

A vessel contains a mixture of equal weights of oxygen and SO_2 at a pressure of 600mm of Hg. The partial pressure of oxygen in mm is

The decomposition of O_(3)(g) follows first order kinetics and is given by O_(3)(g) rarr O_(2)(g)+O(g) The rate constant for this reaction is 1.0xx10^(-3)s^(-1) . The initial pressure of O_(3)(g) is 100 atm. What will be the partial pressure ( in atm ) of O_(3), O_(2), O respectively after 38.38 minutes ?

N_(2(g)) + 3H_(2(g)) hArr 2NH_(3(g)) for the reaction initially the mole ratio was 1: 3 of N_(2). H_(2) . At equilibrium 50% of each has reacted. If the equilibrium pressure is p, the partial pressure of NH_(3) at equilibrium is

At 627^(@) C and one atmosphere SO_(3) is is partially dissociated into SO_(2) and O_(2) by SO_(3(g)) hArr SO_(2(g)) + (1)/(2) O_(2(g)). The density of the equilibrium mixture is 0.925 g/litre. What is the degree of dissociation ?